16s^2+56s=49

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Solution for 16s^2+56s=49 equation:



16s^2+56s=49
We move all terms to the left:
16s^2+56s-(49)=0
a = 16; b = 56; c = -49;
Δ = b2-4ac
Δ = 562-4·16·(-49)
Δ = 6272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6272}=\sqrt{3136*2}=\sqrt{3136}*\sqrt{2}=56\sqrt{2}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56\sqrt{2}}{2*16}=\frac{-56-56\sqrt{2}}{32} $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56\sqrt{2}}{2*16}=\frac{-56+56\sqrt{2}}{32} $

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